College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 8, Sequences and Series - Section 8.1 - Sequences and Summation Notation - 8.1 Exercises: 49

Answer

$\frac{11}{6}$

Work Step by Step

We evaluate the sum: $\sum_{k=1}^{3} \frac{1}{k}=\frac{1}{1}+\frac{1}{2}+\frac{1}{3}=\frac{6}{6}+\frac{3}{6}+\frac{2}{6}=\frac{11}{6}$
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