Answer
0.153146
Work Step by Step
We evaluate using a calculator:
$\sum_{j=5}^{15}=\frac{1}{j^2+1}=\frac{1}{5^2+1}+\frac{1}{6^2+1}+...+\frac{1}{15^2+1}=0.153146$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 8, Sequences and Series - Section 8.1 - Sequences and Summation Notation - 8.1 Exercises - Page 601: 58
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