College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 8, Sequences and Series - Section 8.1 - Sequences and Summation Notation - 8.1 Exercises: 58

Answer

0.153146

Work Step by Step

We evaluate using a calculator: $\sum_{j=5}^{15}=\frac{1}{j^2+1}=\frac{1}{5^2+1}+\frac{1}{6^2+1}+...+\frac{1}{15^2+1}=0.153146$
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