Answer
$\sqrt{4}+\sqrt{5}+\sqrt{6}+\sqrt{7}+\sqrt{8}+\sqrt{9}+\sqrt{10}$
Work Step by Step
We expand the sum:
$\sum_{k=0}^{6}\sqrt{k+4}=\sqrt{0+4}+\sqrt{1+4}+\sqrt{2+4}+\sqrt{3+4}+\sqrt{4+4}+\sqrt{5+4}+\sqrt{6+4}=\sqrt{4}+\sqrt{5}+\sqrt{6}+\sqrt{7}+\sqrt{8}+\sqrt{9}+\sqrt{10}$
