Answer
$S_{1}=1$
$S_{2}=5$
$S_{3}=14$
$S_{4}=30$
$S_{5}=55$
$S_{6}=91$
Work Step by Step
We are given:
$1^2, 2^2, 3^2, 4^2$ ...
We notice that the pattern is the square of the next integer:
$a_1=1^{2}$
$a_2=2^{2}$
$a_3=3^{2}$
$a_4=4^{2}$
Therefore:
$a_{n}=n^{2}$
So:
$a_5=5^{2}$
$a_6=6^{2}$
We find the partial sums:
$S_{1}=1^{2}=1$
$S_{2}=1+2^{2}=5$
$S_{3}=5+3^{2}=5+9=14$
$S_{4}=14+4^{2}=14+16=30$
$S_{5}=30+5^{2}=30+25=55$
$S_{6}=55+6^{2}=55+36=91$