Answer
(a) $x=-2$
(b) $x=32$
Work Step by Step
(a)
We are given:
$\log_{7}(\frac{1}{49})=x$
This means:
$7^{x}=\frac{1}{49}$
Therefore:
$x=-2$
(b)
We are given:
$\log_{2}x=5$
This means:
$2^{5}=x$
Therefore:
$x=32$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 4, Exponential and Logarithmic Functions - Section 4.3 - Logarithmic Functions - 4.3 Exercises - Page 388: 39
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