Answer
(a) $\log_4{0.125}=-\frac{3}{2}$
(b) $\log_7{343}=3$
Work Step by Step
RECALL:
$b^y=x \longrightarrow \log_b{x}=y$
Use the rule above to obtain:
(a) $\log_4{0.125}=-\frac{3}{2}$
(b) $\log_7{343}=3$
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