Answer
(a) $x=2$
(b) $x=4$
Work Step by Step
(a)
We are given:
$\log_{x}16=4$
This means:
$x^{4}=16$
$x=\pm \sqrt[4]{16}=\pm 2$
$x=2$
(a log base can't be negative)
(b)
$\log_{x}8=\frac{3}{2}$
This means:
$ x^{3/2}=8$
$ x=8^{2/3}=4$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 4, Exponential and Logarithmic Functions - Section 4.3 - Logarithmic Functions - 4.3 Exercises - Page 388: 43
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
