Answer
(a) $5$
(b) $17$
(c) $0$
Work Step by Step
RECALL:
(1) $\log_b{b}=1$
(2) $\log_b{1}=0$
(3) $\log_b{b^x}=x$
(a) Write $32$ as $2^5$, then use rule (3) above to obtain:
$=\log_2{2^5}
\\=5$
(b) Use rule (3) above to obtain:
$=\log_8{8^{17}}
\\=17$
(c) Use rule (2) above to obtain:
$\log_6{1}=0$
