## College Algebra 7th Edition

Domain: $(-\infty,\ \infty)$
We are given: $f(t)=\sqrt[3]{t-1}$ The domain of a function consists of all values that $x$ is allowed to have. In this case, there are no restrictions on $x$ (we can take the cube root of positive and negative values). Thus the domain is: $(-\infty,\ \infty)$