College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Section 2.1 - Functions - 2.1 Exercises: 37

Answer

$f(x^{2})=x^{2}+4$ $(f(x))^{2}=x^{2}+8x+16$

Work Step by Step

We are given: $f(x)=x+4$ We evaluate: $f(x^{2})=x^{2}+4$ $(f(x))^{2}=(x+4)^{2}=x^{2}+8x+16$
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