College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Section 2.1 - Functions - 2.1 Exercises: 42

Answer

$h(6)-h(-3)=27$

Work Step by Step

We are given: $h(t)=t^{2}+5$ We evaluate: $h(-3)=(-3)^{2}+5=9+5=14$ $h(6)=6^{2}+5=36+5=41$ $h(6)-h(-3)=41-14=27$
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