College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Section 2.1 - Functions - 2.1 Exercises: 35

Answer

$f(x+2)=x^{2}+4x+5$ $f(x)+f(2)=x^{2}+6$

Work Step by Step

We are given: $f(x)=x^2+1$ We evaluate: $f(x+2)=(x+2)^{2}+1=x^{2}+4x+4+1=x^{2}+4x+5$ $f(x)+f(2)=x^{2}+1+(2)^{2}+1=x^{2}+1+4+1=x^{2}+6$
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