## College Algebra 7th Edition

Net change: 35 Average rate of change: $\frac{7}{4}$
We find the net change from $x=10$ to $x=30$: $g(30)-g(10)=30--5=35$ Next we find the average rate of change for this interval: $\frac{g(30)-g(10)}{30-10}=\frac{35}{20}=\frac{7}{4}$