## College Algebra 7th Edition

the domain is: $\{x|x\neq-4\}$
We are given: $f(x)= \frac{\sqrt[3]{2x+1}}{\sqrt[3]{2x}+2}$ We know that the denominator can not be 0: $\sqrt[3]{2x}+2\neq 0$ $\sqrt[3]{2x}\neq-2$ $2x\neq(-2)^3$ $2x\neq-8$ $x\neq-4$ Therefore, the domain is: $\{x|x\neq-4\}$.