Answer
Yes.
Work Step by Step
We are given:
$x^{3}-y^{3}=27$
We solve for $y$:
$ y^{3}=x^{3}-27$
$ y=(x^{3}-27)^{1/3}$
We see that this is indeed a function, since the cubic root provides only one $y$ value for each $x$ value.
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 2, Functions - Chapter 2 Review - Exercises - Page 268: 41
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