College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Chapter 2 Review - Exercises: 42

Answer

No.

Work Step by Step

We are given: $2x=y^{4}-16$ We solve for $y$: $y^{4}=2x+16$ $y=\pm\sqrt[4]{2x+16}$ Since $y$ can have two values for the same $x$ value (the positive and negative), $y$ does not define a function of $x$.
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