College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Chapter 1 Review - Exercises: 54

Answer

$ x=2$ or $x=\pm\sqrt{5}$

Work Step by Step

We factor by grouping and solve: $x^{3}-2x^{2}-5x+10=0$ $x^{2}(x-2)-5(x-2)=0$ $(x-2)(x^{2}-5)=0$ $x-2=0$ or $x^2-5=0$ $ x=2$ or $x=\pm\sqrt{5}$
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