Answer
$x=0$ or $x=\frac{5}{2}$ or $x=-\frac{5}{2}$
Work Step by Step
We solve by factoring:
$4x^{3}-25x=0$
$x(4x^{2}-25)=0$
$x(2x-5)(2x+5)=0$
$x=0$ or $2x-5=0$ or $2x+5=0$
$x=0$ or $x=\frac{5}{2}$ or $x=-\frac{5}{2}$
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