Answer
$x=\frac{1}{2}$ or $x=-1$
Work Step by Step
We solve by factoring:
$2x^{2}+x=1$
$ 2x^{2}+x-1=0$
$(2x-1)(x+1)=0$
$2x-1=0$ or $x+1$=0
$x=\frac{1}{2}$ or $x=-1$
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