College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Section 2.4 - Circles - 2.4 Assess Your Understanding: 38

Answer

$(x-1)^2+y^2=20$

Work Step by Step

RECALL: The standard equation of a circle whose center is at the origin is: $(x-h)^2+(y-k)^2=r^2$ where $r$ = radius With its center at $(1, 0)$, the tentative equation of the given circle is: $(x-1)^2+(y-0)^2=r^2 \\(x-1)^2+y^2=r^2$ To find the value of $r^2$, substitute the x and y values of the given point into the tentative equation above to obtain: $(x-1)^2+y^2=r^2 \\(-3-1)^2+2^2=r^2 \\(-4)^2+4=r^2 \\16+4=r^2 \\20=r^2$ Therefore, the standard form of the equation of the the given circle is: $(x-1)^2+y^2=20$
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