## College Algebra (10th Edition)

(a) center: $(0, 0)$ radius = $2$ (b) Refer to the image below for the graph. (c) x-intercepts: $-2$ and $2$ y-intercepts: $-2$ and $2$
RECALL: The standard form of a circle's equation is: $(x-h)^2 +(y-k)^2=r^2$ where $r$ = radius and $(h, k)$ is the center. The given equation can be written as: $(x-0)^2+(y-0)^2 = 2^2$ Thus, (a) The given circle has: center: $(h, k)=(0, 0)$ radius = $r=2$ (b) To graph the circle, perform the following steps: (1) Plot the center $(0, 0)$. (2) With a radius of $2$ units, plot the following points: 2 units to the left of the center: $(-2, 0)$ 2 units to the right of the center: $(2, 0)$ 2 units above the center: $(0, 2)$ 2 units below the center: $(0, -2)$ (3) Connect the four points above (not including the center) using a smooth curve to form a circle (Refer to the attached image in the answer part above for the graph.) (c) The graph shows that the circle has the following intercepts: x-intercepts: $-2$ and $2$ y-intercepts: $-2$ and $2$