Answer
$x=\left\{-1, 5\right\}$
Work Step by Step
Take the square root of both sides to obtain:
$\sqrt{(x-2)^2}=\pm\sqrt9
\\x-2 = \pm 3$
Add $2$ on both sides to obtain:
$x=2\pm3$
Thus,
$x_1 =2+3=5
\\x_1=2-3=-1$
Therefore, the solutions are:
$x=\left\{-1, 5\right\}$
