Answer
$-1\lt x\lt 1$
Work Step by Step
We know that the solution to the inequality $x^2\lt a$ is equivalent to:
$-\sqrt{a}\lt x\lt \sqrt{a}$
Therefore:
$x^{2}\lt 1$
$-\sqrt{1}\lt x\lt \sqrt{1}$
$-1\lt x\lt 1$
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