Answer
$x\leq-1$ or $x\geq 1$
Work Step by Step
We know that the solution to the inequality:
$x^2\gt a$
Is equivalent to:
$x\lt -\sqrt{a}$ or $x\gt \sqrt{a}$
Therefore:
$x^{2}\geq 1$
$x\leq-\sqrt{1}$ or $x\geq\sqrt{1}$
$x\leq-1$ or $x\geq 1$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 1 - Section 1.6 - Equations and Inequalities Involving Absolute Value - 1.6 Assess Your Understanding - Page 134: 88
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