Answer
$a=-1$ and $b=-\frac{1}{15}$
Work Step by Step
We are given:
$|x-2|\leq 7$
$-7\leq x-2\leq 7$
We add $2$:
$-5\leq x\leq 9$
And subtract $10$:
$-15\leq x-10\leq-1$
We take the reciprocal:
$-\frac{1}{15}\geq\frac{1}{x-10}\geq-1$
$-1\leq\frac{1}{x-10}\leq-\frac{1}{15}$
Therefore:
$a=-1$ and $b=-\frac{1}{15}$