College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.6 - Equations and Inequalities Involving Absolute Value - 1.6 Assess Your Understanding: 89

Answer

$-4\leq x\leq 4$

Work Step by Step

We know that the solution to the inequality: $x^2\lt a$ Is equivalent to: $-\sqrt{a}\lt x\lt \sqrt{a}$ Therefore: $x^{2}\leq 16$ $-\sqrt{16}\leq x\leq\sqrt{16}$ $-4\leq x\leq 4$
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