College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.2 - Quadratic Equations - 1.2 Assess Your Understanding: 72

Answer

$\displaystyle x=\frac{-\pi\pm\sqrt{\pi^{2}+8\pi}}{2\pi}$ $x=0.44$ or $x=-1.44$

Work Step by Step

We are given: $\pi x^{2}+\pi x-2=0$ We solve using the quadratic formula ($a=\pi,\ b=\pi,\ c=-2$): $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ $\displaystyle x=\frac{-\pi\pm\sqrt{(\pi)^{2}-4*\pi*-2}}{2*\pi}$ $\displaystyle x=\frac{-\pi\pm\sqrt{\pi^{2}+8\pi}}{2\pi}$ $x=0.44$ or $x=-1.44$
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