## College Algebra (10th Edition)

RECALL The nature of solutions using the quadratic equation $ax^2+bx+c=0$ can be determined using the value of its discriminant $b^2-4ac$. If the value of the discriminant is: (1) negative, then the equation has no real solutions; (2) zero, then the equation has one repeated real solution; and (3) positive, then there are two unequal real solutions. The given quadratic equation has : $a=9 \\b=-30 \\c=25$ Solve for the discriminant to obtain: $=b^2-4ac \\=(-30)^2-4(9)(25) \\=900-900 \\=0$ The discriminant is zero, so the equation has one repeated real solution.