College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.2 - Quadratic Equations - 1.2 Assess Your Understanding - Page 102: 75

Answer

one repeated real solution

Work Step by Step

RECALL The nature of solutions using the quadratic equation $ax^2+bx+c=0$ can be determined using the value of its discriminant $b^2-4ac$. If the value of the discriminant is: (1) negative, then the equation has no real solutions; (2) zero, then the equation has one repeated real solution; and (3) positive, then there are two unequal real solutions. The given quadratic equation has : $a=9 \\b=-30 \\c=25$ Solve for the discriminant to obtain: $=b^2-4ac \\=(-30)^2-4(9)(25) \\=900-900 \\=0$ The discriminant is zero, so the equation has one repeated real solution.
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