College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.2 - Quadratic Equations - 1.2 Assess Your Understanding: 63

Answer

$x=\frac{1\pm\sqrt{33}}{8}$

Work Step by Step

$4-\displaystyle \frac{1}{x}-\frac{2}{x^{2}}=0$ We multiply by $x^2$: $x^{2}(4-\frac{1}{x}-\frac{2}{x^{2}})=x^{2}*0$ $4x^{2}-x-2=0$ We solve using the quadratic formula ($a=4,\ b=-1,\ c=-2$): $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ $x=\frac{-(-1)\pm\sqrt{(-1)^{2}-4*4*-2}}{2*4}$ $x=\frac{1\pm\sqrt{1+32}}{8}$ $x=\frac{1\pm\sqrt{33}}{8}$
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