College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.2 - Quadratic Equations - 1.2 Assess Your Understanding: 48

Answer

The solution set is {$-\frac{3}{2},-1$}.

Work Step by Step

$2x^2+5x+3=0$ $a=2, b=5, c=3$ $D=b^2-4ac=(5)^2-4\cdot2(3)=25-24=1>0$ The equation has two real solutions. $x=\frac{-b\pm\sqrt {b^2-4ac}}{2a}=\frac{5\pm\sqrt 1}{2\cdot2}$ Use the quadratic formula. $x=\frac{-5\pm\sqrt 1}{4}$ Simplify $x=\frac{-5+1}{4}=-1$ $x=\frac{-5-1}{4}=\frac{-6}{4}=-\frac{3}{2}$ The solution set is {$-\frac{3}{2},-1$}.
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