Answer
The solution set is {$\frac{1}{3}$}.
Work Step by Step
$9t^2-6t+1=0$
$a=9, b=-6, c=1$
$D=b^2-4ac=(-6)^2-4\cdot9\cdot1=36-36=0$. The equation has one real solution.
$t=\frac{-b\pm\sqrt {b^2-4ac}}{2a}=\frac{6\pm\sqrt 0}{2\cdot9}$ Use the quadratic formula.
$t=\frac{6}{18}$
$t=\frac{1}{3}$,
The solution set is {$\frac{1}{3}$}.
