## College Algebra (10th Edition)

Published by Pearson

# Chapter 1 - Section 1.2 - Quadratic Equations - 1.2 Assess Your Understanding: 13

#### Answer

$\left\{-5, 5\right\}$

#### Work Step by Step

Write 25 as $5^2$ to obtain: $x^2-5^2=0$ Factor the difference of two squares using the formula $a^2-b^2=(a-b)(a+b)$ to obtain: $(x-5)(x+5)=0$ Use the Zero-Product Property by equating each factor to zero then solving equation to obtain: $\begin{array}{ccc} &x-5=0 &\text{ or } &x+5=0 \\&x=5 &\text{ or } &x=-5 \end{array}$ Thus, the solution set is $\left\{-5, 5\right\}$.

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