## College Algebra (10th Edition)

The solution et is {$-\frac{2}{3},\frac{3}{2}$}.
$6x-5=\frac{6}{x}$ Clear fractions by multiply by x. $6x^2-5x-6=0$ $(2x-3)(3x+2)=0$ Factor. $2x-3=0$ or $3x+2=0$ Set each factor equal to $0$. $2x=3$ or $3x=-2$ $x=\frac{3}{2}$ or $x=-\frac{2}{3}$ The solution set is {$-\frac{2}{3},\frac{3}{2}$}.