Answer
The solution et is {$-\frac{2}{3},\frac{3}{2}$}.
Work Step by Step
$6x-5=\frac{6}{x}$ Clear fractions by multiply by x.
$6x^2-5x-6=0$
$(2x-3)(3x+2)=0$ Factor.
$2x-3=0$ or $3x+2=0$ Set each factor equal to $0$.
$2x=3$ or $3x=-2$
$x=\frac{3}{2}$ or $x=-\frac{2}{3}$
The solution set is {$-\frac{2}{3},\frac{3}{2}$}.
