Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Review: 20

Answer

$\dfrac{4x+4y}{xy^{2}}\div\dfrac{3x+3y}{x^{2}y}=\dfrac{4x}{3y}$

Work Step by Step

$\dfrac{4x+4y}{xy^{2}}\div\dfrac{3x+3y}{x^{2}y}$ Take out common factor $4$ from the numerator of the first fraction and common factor $3$ from the numerator of the second fraction: $\dfrac{4x+4y}{xy^{2}}\div\dfrac{3x+3y}{x^{2}y}=\dfrac{4(x+y)}{xy^{2}}\div\dfrac{3(x+y)}{x^{2}y}=...$ Evaluate the division and simplify by removing the factors that appear both in the numerator and the denominator of the resulting expression: $...=\dfrac{4(x+y)x^{2}y}{3(x+y)xy^{2}}=\dfrac{4x^{2}y}{3xy^{2}}=\dfrac{4x}{3y}$
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