Answer
$\dfrac{x^{2}-x-6}{x^{2}-3x-10}=\dfrac{x-3}{x-5}$
Work Step by Step
$\dfrac{x^{2}-x-6}{x^{2}-3x-10}$
Factor the numerator and the denominator and then simplify:$\dfrac{x^{2}-x-6}{x^{2}-3x-10}=\dfrac{(x-3)(x+2)}{(x-5)(x+2)}=\dfrac{x-3}{x-5}$
