Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Review: 21

Answer

$\dfrac{x^{2}+x-42}{x-3}\cdot\dfrac{(x-3)^{2}}{x+7}=(x-3)(x+6)$

Work Step by Step

$\dfrac{x^{2}+x-42}{x-3}\cdot\dfrac{(x-3)^{2}}{x+7}$ Factor the numerator of the first fraction: $\dfrac{x^{2}+x-42}{x-3}\cdot\dfrac{(x-3)^{2}}{x+7}=\dfrac{(x+7)(x-6)}{x-3}\cdot\dfrac{(x-3)^{2}}{x+7}=...$ Evaluate the product and simplify by removing the factors that appear both in numerator and the denominator of the resulting expression: $...=\dfrac{(x-3)^{2}(x+7)(x-6)}{(x-3)(x+7)}=(x-3)(x-6)$
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