## Algebra: A Combined Approach (4th Edition)

$\dfrac{x^{2}+x-42}{x-3}\cdot\dfrac{(x-3)^{2}}{x+7}=(x-3)(x+6)$
$\dfrac{x^{2}+x-42}{x-3}\cdot\dfrac{(x-3)^{2}}{x+7}$ Factor the numerator of the first fraction: $\dfrac{x^{2}+x-42}{x-3}\cdot\dfrac{(x-3)^{2}}{x+7}=\dfrac{(x+7)(x-6)}{x-3}\cdot\dfrac{(x-3)^{2}}{x+7}=...$ Evaluate the product and simplify by removing the factors that appear both in numerator and the denominator of the resulting expression: $...=\dfrac{(x-3)^{2}(x+7)(x-6)}{(x-3)(x+7)}=(x-3)(x-6)$