Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Review: 12

Answer

$\dfrac{x^{2}-2x}{x^{2}+2x-8}=\dfrac{x}{x+4}$

Work Step by Step

$\dfrac{x^{2}-2x}{x^{2}+2x-8}$ Take out common factor $x$ from the numerator and factor the denominator, then simplify: $\dfrac{x^{2}-2x}{x^{2}+2x-8}=\dfrac{x(x-2)}{(x+4)(x-2)}=\dfrac{x}{x+4}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.