Answer
$\frac{30}{(x+3)}$
Work Step by Step
$\frac{6x^{2}-18x}{3x^{2}-2x}\times\frac{15x-10}{x^{2}-9}$
=$\frac{6x(x-3)}{x(3x-2)}\times\frac{5(3x-2)}{x^{2}-3^{2}}$
=$\frac{6x(x-3)}{x(3x-2)}\times\frac{5(3x-2)}{(x+3)(x-3)}$
=$\frac{6x}{x(3x-2)}\times\frac{5(3x-2)}{(x+3)}$
=$\frac{6x}{x}\times\frac{5}{(x+3)}$
=$\frac{6}{1}\times\frac{5}{(x+3)}$
=$\frac{30}{(x+3)}$
