Answer
$3x-5$
Work Step by Step
$\frac{3x^{2}+2x}{x-1}-\frac{10x-5}{x-1}$
=$\frac{3x^{2}+2x-(10x-5)}{x-1}$
=$\frac{3x^{2}+2x-10x+5}{x-1}$
=$\frac{3x^{2}-8x+5}{x-1}$
=$\frac{3x^{2}-3x-5x+5}{x-1}$
=$\frac{3x(x-1)-5(x-1)}{x-1}$
=$\frac{(x-1)(3x-5)}{x-1}$
=$3x-5$
