Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Cumulative Review: 41

Answer

$\frac{2}{5}$

Work Step by Step

Step 1: $\frac{x^{2}+x}{3x}\times\frac{6}{5x+5}$ Step 2: $\frac{x(x+1)}{3x}\times\frac{6}{5(x+1)}$ Step 3: Cancelling $(x+1)$ as it is found in both numerator and denominator, we get $\frac{x}{3x}\times\frac{6}{5}$. Step 4: Cancelling $(x)$ as it is found in both numerator and denominator, we get $\frac{1}{3}\times\frac{6}{5}$. Step 5: Now the expression becomes $\frac{6}{3\times5}$. Step 6: After simplifying, the expression becomes $\frac{2}{5}$.
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