Answer
$\dfrac{3}{x-2}$
Work Step by Step
$\dfrac{6x}{x^2-4}-\dfrac{3}{x+2}$
$\dfrac{6x}{x^2-2^2}-\dfrac{3}{x+2}$
$\dfrac{6x}{(x+2)(x-2)}-\dfrac{3}{x+2}$
$\dfrac{6x(x+2)-3(x+2)(x-2)}{(x+2)(x-2)(x+2)}$
$\dfrac{6x-3(x-2)}{(x+2)(x-2)}$
$\dfrac{6x-3x+6}{(x+2)(x-2)}$
$\dfrac{3x+6}{(x+2)(x-2)}$
$\dfrac{3(x+2)}{(x+2)(x-2)}$
$\dfrac{3}{x-2}$
