## Algebra: A Combined Approach (4th Edition)

Published by Pearson

# Chapter 5 - Test: 30

#### Answer

$x+2$

#### Work Step by Step

Given $(x^2+7x+10)\div(x+5) = \dfrac{x^2+7x+10}{x+5}$ Factoring the numerator: $\dfrac{x^2+7x+10}{x+5} = \dfrac{(x+2)(x+5)}{x+5}$ Simplifying: $\dfrac{(x+2)(x+5)}{x+5} = x+2$

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