Answer
$9x^{2}-\frac{1}{25}$
Work Step by Step
Step 1: $(3x-\frac{1}{5})(3x+\frac{1}{5})$
Step 2: $3x(3x+\frac{1}{5})-\frac{1}{5}(3x+\frac{1}{5})$
Step 3: $9x^{2}+\frac{3x}{5}-\frac{3x}{5}-\frac{1}{5}(\frac{1}{5})$
Step 4: $9x^{2}-\frac{1}{25}$