Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Test: 27

Answer

$t=0; h=1001$ $t=1; h=985$ $t=3; h=857$ $t=5; h=601$

Work Step by Step

$-16t^2+1001$ $t=0$ $-16t^2+1001$ $=-16(0)^2+1001$ $=1001$ $t=1$ $-16t^2+1001$ $=-16(1)^2+1001$ $=1001-16$ $=985$ $t=3$ $-16t^2+1001$ $=-16(3)^2+1001$ $=1001-16(9)$ $=1001-144$ $=857$ $t=5$ $-16t^2+1001$ $=-16(5)^2+1001$ $=1001-16(25)$ $=1001-400$ $=601$
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