Answer
$3x^{2}+16x-35$
Work Step by Step
$(x+7)(3x-5)$
FOIL --> First, Outer, Inner, Last
Multiply the first numbers together:
$x \times 3x = 3x^{2}$
Multiply the outer numbers together:
$x \times -5 = -5x$
Multiply the inner numbers together:
$7 \times 3x = 21x$
Multiply the last numbers together:
$7 \times -5 = -35$
Add together and simplify:
$3x^{2}+21x-5x-35$
$3x^{2}+16x-35$