Answer
$x^{7}y$
Work Step by Step
Based on the quotient rule for exponents, we know that $\frac{a^{m}}{{a}^{n}}=a^{m-n}, a\ne0$ (where $m$ and $n$ are positive integers and $a$ is a real number).
Therefore, $\frac{x^{8}y^{6}}{xy^{5}}=x^{8-1}\times y^{6-5}=x^{7}\times y^{1}=x^{7}y$.