Answer
-7
Work Step by Step
We know that $a^{0}=1$ (where $a$ is a nonzero real number).
Therefore, $-7x^{0}=-7\times x^{0}=-7\times1=-7$.
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 5 - Section 5.1 - Exponents - Exercise Set - Page 344: 67
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