Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.1 - Exponents - Exercise Set: 61

Answer

$\frac{y^{3}}{2}$

Work Step by Step

Based on the quotient rule for exponents, we know that $\frac{a^{m}}{{a}^{n}}=a^{m-n}, a\ne0$ (where $m$ and $n$ are positive integers and $a$ is a real number). Therefore, $\frac{7x^{2}y^{6}}{14x^{2}y^{3}}=\frac{7}{14}\times x^{2-2}\times y^{6-3}=\frac{1}{2}\times x^{0}\times y^{3}=\frac{y^{3}}{2}$. Recall that $x^{0}=1$.
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