Answer
$\frac{y^{3}}{2}$
Work Step by Step
Based on the quotient rule for exponents, we know that $\frac{a^{m}}{{a}^{n}}=a^{m-n}, a\ne0$ (where $m$ and $n$ are positive integers and $a$ is a real number).
Therefore, $\frac{7x^{2}y^{6}}{14x^{2}y^{3}}=\frac{7}{14}\times x^{2-2}\times y^{6-3}=\frac{1}{2}\times x^{0}\times y^{3}=\frac{y^{3}}{2}$.
Recall that $x^{0}=1$.
