## Algebra: A Combined Approach (4th Edition)

$18y^{17}$ meters
We are given that the parallelogram has base length of $9y^{7}$ meters and height of $2y^{10}$ meters. We know that the area of a parallelogram is calculated as $area=base \times height$. Based on the product rule for exponents, we know that $a^{m}\times a^{n}=a^{m+n}$ (where $m$ and $n$ are positive integers and $a$ is a real number). Therefore, $area=9y^{7}\times2y^{10}=9\times2\times y^{7+10}=18y^{17}$ meters.