Answer
$(\frac{5}{6}, -\frac{1}{2})$
Work Step by Step
$3x+\frac{7}{2}y=\frac{3}{4}$
$-\frac{x}{2}+\frac{5}{3}y=-\frac{5}{4}$
Multiply first equation by 4 and second equation by 12.
$12x+14y=3$
$-6x+20y=-15$
Multiply the second equation by 2.
$12x+14y=3$
$-12x+40y=-30$
Add both equations.
$54y=-27$
$y=-\frac{1}{2}$
Solve for $x$.
$3x+\frac{7}{2}y=\frac{3}{4}$
$3x+\frac{7}{2}(-\frac{1}{2})=\frac{3}{4}$
$3x-\frac{7}{4}=\frac{3}{4}$
$12x-7=3$
$12x=10$
$x=\frac{5}{6}$
$x=\frac{5}{6}$
$y=-\frac{1}{2}$
$(\frac{5}{6}, -\frac{1}{2})$
